( 1 ) y 2 = y 1 2 ( ( 1 + 8 F r 1 2 ) − 1 ) ( 2 ) F r 1 = v ( g y 1 ) 1 / 2 = q y 1 ( g y 1 ) 1 / 2 ( 3 ) F r 1 2 = q 2 g y 1 3 = ( 10 ) 2 32.2 ∗ ( 0.24 3 ) = 224.65 ( 4 ) y 2 = 0.24 2 ( 1 + 8 ( 224.65 ) ) − 1 = 4.97 f t ( 5 ) M 1 = ( 0.24 ) 2 2 + q 2 g ∗ ( 0.24 ) = 13 f t 2 ( 6 ) M 2 = ( 4.97 ) 2 2 + q 2 g ∗ ( 4.97 ) = 13 f t 2 {\displaystyle {\begin{aligned}(1)&\qquad y_{2}={\frac {y_{1}}{2}}\left({\sqrt {(1+8{Fr_{1}}^{2})}}-1\right)\\(2)&\qquad Fr_{1}={\frac {v}{(gy_{1})^{1/2}}}={\frac {q}{y_{1}(gy_{1})^{1/2}}}\\(3)&\qquad {Fr_{1}}^{2}={\frac {q^{2}}{{gy_{1}}^{3}}}={\frac {(10)^{2}}{32.2^{*}(0.24^{3})}}=224.65\\(4)&\qquad y_{2}={\frac {0.24}{2}}{\sqrt {(1+8(224.65))}}-1=4.97\ ft\\(5)&\qquad M_{1}={\frac {(0.24)^{2}}{2}}+{\frac {q^{2}}{g^{*}(0.24)}}=13\ ft^{2}\\(6)&\qquad M_{2}={\frac {(4.97)^{2}}{2}}+{\frac {q^{2}}{g^{*}(4.97)}}=13\ ft^{2}\end{aligned}}}